AP EAMCET · PHYSICS · Communication System
A radio receiver antenna that is \(4 \mathrm{~m}\) long is oriented along the direction of the
electromagnetic wave and it receives a signal of intensity \(8 \times 10^{-16} \mathrm{Wm}^{-2}\). The maximum instantaneous potential difference across the two ends of the antenna is
- A \(1.23 \mu \mathrm{V}\)
- B \(3.1 \mu \mathrm{V}\)
- C \(31 \mu \mathrm{V}\)
- D \(7.76 \mu \mathrm{V}\)
Answer & Solution
Correct Answer
(B) \(3.1 \mu \mathrm{V}\)
Step-by-step Solution
Detailed explanation
Given that, length of antenna, \(l=4 \mathrm{~m}\) Intensity of signal, \(I=8 \times 10^{-16} \mathrm{~W} / \mathrm{m}^2\) Using, \(I=\frac{1}{2} \varepsilon_0 c E_0^2 \Rightarrow E_0=\sqrt{\frac{2 I}{\varepsilon_0 c}}\) By substituting the values, we get…
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