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AP EAMCET · PHYSICS · Dual Nature of Matter

A beam of light with intensity 10-3 N m-2 and cross sectional area 20 cm2 is incident on a fully reflective surface at angle 45°. Then the force exerted by the beam on the surface is

  1. A 2.3×10-15 N
  2. B 1.33×10-14 N
  3. C 6.67×10-15 N
  4. D 9.4×10-15 N
Verified Solution

Answer & Solution

Correct Answer

(D) 9.4×10-15 N

Step-by-step Solution

Detailed explanation

Force exerted by the beam on the surface is given by F=∆p∆t=2IAcosθc Given here: I=10-3 N m-2, A=20 cm2 and θ=45°. Putting the values, we get F=2×10-3×20×10-4×cos45°3×108=9.4×10-15 N
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