AP EAMCET · PHYSICS · Ray Optics
A beam of light is incident from air on the surface of a liquid. The angle of incidence is \(\theta\) and the angle of refraction is \(\alpha\). If the critical angle for liquid when surrounded by air is \(\theta_c\) then \(\sin \theta_c\) is
- A \(\frac{\sin \alpha}{\sin \theta}\)
- B \(\sin \alpha \times \sin \theta\)
- C \(\frac{\sin \theta}{\sin \alpha}\)
- D \(\frac{\sin \alpha}{\cos \theta}\)
Answer & Solution
Correct Answer
(A) \(\frac{\sin \alpha}{\sin \theta}\)
Step-by-step Solution
Detailed explanation
Refractive index of liquid with respect to air, \(n_{l a}=\frac{\sin i}{\sin r}\) Here, \(i=\theta\) and \(r=\alpha\) So, refractive index of liquid with respect to air, \(n_{l a}=\frac{\sin \theta}{\sin \alpha}\) Now, if \(\theta_c=\) angle of critical incidence for liquid…
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