AP EAMCET · PHYSICS · Center of Mass Momentum and Collision
A ball \(P\) moving with a speed of \(v \mathrm{~ms}^{-1}\) collides directly with another identical ball \(Q\) moving with a speed \(10 \mathrm{~ms}^{-1}\) in the opposite direction. \(P\) comes to rest after the collision. If the coefficient of restitution is 0.6 , the value of \(v\) is
- A \(30\ ms^{-1}\)
- B \(40\ ms^{-1}\)
- C \(50\ ms^{-1}\)
- D \(60\ ms^{-1}\)
Answer & Solution
Correct Answer
(B) \(40\ ms^{-1}\)
Step-by-step Solution
Detailed explanation
From conservation of moment, \(\begin{aligned} & m(v-10)=m v_2 \\ & v_2=(v-10) \\ & \longrightarrow \mathrm{V} \stackrel{10}{\bullet} \mathrm{m} / \mathrm{s} \\ & \mathrm{V}=0 \quad \mathrm{~V}_2 \quad \text { Berore } \end{aligned}\) The coefficient of restitution,…
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