AP EAMCET · PHYSICS · Alternating Current
A \(70 \mathrm{mH}\) inductor is connected to \(220 \mathrm{~V}, 50 \mathrm{~Hz} \mathrm{AC}\) supply. The rms value of the current in the circuit is
- A \(\frac{100}{\sqrt{2} \pi} \mathrm{A}\)
- B \(10 \mathrm{~A}\)
- C \(\frac{50}{\pi} \mathrm{A}\)
- D \(\frac{10 \sqrt{2}}{\pi} \mathrm{A}\)
Answer & Solution
Correct Answer
(B) \(10 \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
As \(i_{\mathrm{rms}}=\frac{\mathrm{V}_{\mathrm{rms}}}{\chi_{\mathrm{L}}}=\frac{\mathrm{V}_{\mathrm{rms}}}{\omega \mathrm{L}}=\frac{220}{2 \pi \times 50 \times 70 \times 10^{-3}}=10 \mathrm{~A}\)
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