AP EAMCET · Maths · Limits
\(\lim _{x \rightarrow 0}\left[\frac{1}{x}-\frac{1}{e^x-1}\right]=\)
- A 0
- B 1
- C 2
- D \(\frac{1}{2}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
\(\lim _{x \rightarrow 0}\left[\frac{1}{x}-\frac{1}{e^x-1}\right]=\lim _{x \rightarrow 0}\left[\frac{e^x-1-x}{x e^x-x}\right]\left[\frac{0}{0} \text { form }\right]\) Applying L's Hopital rule…
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