AP EAMCET · Maths · Basic of Mathematics
The ten's digit in \(1 !+4 !+7 !+10 !+12 !+13 !+15 !+16 !+17 !\) is divisible by
- A 4 !
- B 3 !
- C 5 !
- D 7 !
Answer & Solution
Correct Answer
(A) 4 !
Step-by-step Solution
Detailed explanation
\(\begin{gathered} \text { } 1 !+4 !+7 !=1+24+5040 \\ 1 !+4 !+7 !=5065 \\ (10 !+12 !+\ldots+17 !) \text { this value } \end{gathered}\) have last 2 digits as zero es So, \(10^{\prime}\) 's digit of given question is same as \(10^{\prime} \mathrm{s}\) digit of \((1 !+4 !+7 !)\)…
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