AP EAMCET · Maths · Circle
The radical centre of the circles \(x^2+y^2+3 x+2 y+1=0\) \(x^2+y^2-x+6 y+5=0\) and \(x^2+y^2+5 x-8 y+15=0\) is
- A \((3,2)\)
- B \((-3,-2)\).
- C \((2,3)\)
- D \((-2,-3)\)
Answer & Solution
Correct Answer
(A) \((3,2)\)
Step-by-step Solution
Detailed explanation
\[ \begin{aligned} & \text { Let } S_1: x^2+y^2+3 x+2 y+1=0 \\ & S_2: x^2+y^2-x+6 y+5=0 \\ & S_3: x^2+y^2+5 x-8 y+15=0 \end{aligned} \] Let \((x, y)\) be the radical centre, then \(S_1-S_2=0\) and…
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