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AP EAMCET · Maths · Three Dimensional Geometry

The point in the xy-plane which is equidistant from the points \(\mathrm{A}(2,0,3), \mathrm{B}(0,3,2)\) and \(\mathrm{C}(0,0,1)\) has the coordinates

  1. A \((3,2,0)\)
  2. B \((2,3,0)\)
  3. C \((2,0,8)\)
  4. D \((0,3,1)\)
Verified Solution

Answer & Solution

Correct Answer

(A) \((3,2,0)\)

Step-by-step Solution

Detailed explanation

Let the point in the xy-plane be \(P(x,y,0)\). \(PA^2 = PC^2 \Rightarrow (x-2)^2 + y^2 + (0-3)^2 = x^2 + y^2 + (0-1)^2\) \((x-2)^2 + 9 = x^2 + 1\) \(x^2 - 4x + 4 + 9 = x^2 + 1\) \(-4x + 13 = 1 \Rightarrow -4x = -12 \Rightarrow x = 3\)…
From AP EAMCET
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