AP EAMCET · Maths · Straight Lines
The point \((a, b)\) is the foot of the perpendicular drawn from the point \((3,1)\) to the line \(x+3 y+4=0\). If \((p, q)\) is the image of \((a, b)\) with respect to the line \(3 x-4 y+11=\) 0 , then \(\frac{p}{a}+\frac{q}{b}=\)
- A \(-3\)
- B \(-5\)
- C \(3\)
- D \(7\)
Answer & Solution
Correct Answer
(B) \(-5\)
Step-by-step Solution
Detailed explanation
Since, \((a, b)\) is the foot of perpendicular drawn from \((3,1)\) to the line \(x+3 y+4=0\). \(\Rightarrow a+3 b+4=0...(i)\) Now, equation of a line passing through \((3,1)\) and perpendicular to the given line is \(3 x-y-8=0\) so \(3 a-b-8=0\)...(ii) After solving (i) and…
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