AP EAMCET · Maths · Permutation Combination
The number of integers greater than 6000 that can be formed by using the digits \(0,5,6,7,8\) and 9 without repetition is
- A \(240\)
- B \(840\)
- C \(1440\)
- D \(1680\)
Answer & Solution
Correct Answer
(C) \(1440\)
Step-by-step Solution
Detailed explanation
Number of 4-digit integers: \(d_1 \in \{6,7,8,9\}\) (\(4\) choices); remaining \(3\) digits from \(5\). \(N_4 = 4 \times P(5,3) = 4 \times (5 \times 4 \times 3) = 4 \times 60 = 240\) Number of 5-digit integers: \(d_1 \in \{5,6,7,8,9\}\) (\(5\) choices); remaining \(4\) digits…
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