AP EAMCET · Maths · Straight Lines
The lines \(p\left(p^2+1\right) x-y+q=0\) and \(\left(p^2+1\right)^2 x+\left(p^2+1\right)\) \(y+2 q=0\) are perpendicular to a line \(L\) for
- A exactly one value of \(p\)
- B exactly two values of \(p\)
- C more than two values of \(p\)
- D no value of \(p\)
Answer & Solution
Correct Answer
(A) exactly one value of \(p\)
Step-by-step Solution
Detailed explanation
For 1st line \(m_1=p\left(p^2+1\right)\) for \(2 \mathrm{nd}\) line \(\mathrm{m}_2=-\left(\mathrm{p}^2+1\right)\) Since, if these two line are perpendicular to the line \(\mathrm{L}\) then…
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