AP EAMCET · Maths · Straight Lines
The intercept form of the equation of the straight line passing through the point \((4,-3)\) and perpendicular to the line passing through the points \((1,1)\) and \((2,3)\) is
- A \(\frac{x-4}{1}=\frac{y+3}{1}\)
- B \(\frac{x}{-2}+\frac{y}{-1}=1\)
- C \(\frac{x}{8}-\frac{y}{6}=1\)
- D \(\frac{x}{1}+\frac{y}{1}=1\)
Answer & Solution
Correct Answer
(B) \(\frac{x}{-2}+\frac{y}{-1}=1\)
Step-by-step Solution
Detailed explanation
Let \(\begin{aligned} A & =(4,-3) \\ B & =(1,1) \\ C & =(2,3) \end{aligned}\) Slope of \(B C=\frac{3-1}{2-1}=2\) \(\therefore\) Slope of required line \(=-\frac{1}{2}\) [\(\because\) Lines are perpendicular] \(\therefore\) Equation of line passing through \(A(4,-3)\) and having…
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