AP EAMCET · Maths · Continuity and Differentiability
The function \(f(x)=\sqrt{\frac{3 x^2-5 x-2}{2 x^2-7 x+5}}\) has discontinuous points at \(\mathrm{x}=\)
- A \(5 / 2,2\)
- B \(-1 / 3,2\)
- C \(1,5 / 2\)
- D \(-1 / 3,1\)
Answer & Solution
Correct Answer
(C) \(1,5 / 2\)
Step-by-step Solution
Detailed explanation
Given the function \(f(x)=\sqrt{\frac{3 x^2-5 x-2}{2 x^2-7 x+5}}\) \(=\sqrt{\frac{3 x^2-5 x-2}{2 x^2-2 x-5 x+5}}=\sqrt{\frac{3 x^2-5 x-2}{(2 x-5)(x-1)}}\) So given function is discontinuous at \(x=1, \frac{5}{2}\)
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