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AP EAMCET · Maths · Circle

The equation of the smallest circle passing through the intersection of the line \(x+y=1\) and the circle \(x^2+y^2=9\) is

  1. A \(x^2+y^2-9-(x+y+1)=0\)
  2. B \(x^2+y^2-9-(x+y-1)=0\)
  3. C \(x^2+y^2-9-x+y-1=0\)
  4. D \(x^2+y^2-9+x+y-1=0\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(x^2+y^2-9-(x+y-1)=0\)

Step-by-step Solution

Detailed explanation

The family of circles passes through the intersection of circles \(x^2+y^2=9\) and line \(x+y=1\) is…
From AP EAMCET
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