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AP EAMCET · Maths · Circle

The equation of a circle with centre \((5,4)\) and touch the \(Y\)-axis is

  1. A \(x^2+y^2-10 x-8 y-16=0\)
  2. B \(x^2+y^2-10 x-8 y-61=0\)
  3. C \(x^2+y^2+10 x+8 y+16=0\)
  4. D \(x^2+y^2-10 x-8 y+16=0\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(x^2+y^2-10 x-8 y+16=0\)

Step-by-step Solution

Detailed explanation

Centre \((5,4)\) circle touches \(Y\)-axis So, radius \(=5\) units Equation of circle \(\Rightarrow(x-5)^2+(y-4)^2=5^2\) \(\Rightarrow x^2+y^2-10 x-8 y+16=0\)