AP EAMCET · Maths · Differential Equations
The differential equation formed by eliminating arbitrary constants \(\mathrm{A}, \mathrm{B}\) from the equation \(y=A \cos 3 x+\mathrm{B} \sin 3 x\) is
- A \(\frac{d^2 y}{d x^2}+y=0\)
- B \(\frac{d^2 y}{d x^2}+9 y=0\)
- C \(\frac{d^2 y}{d x^2}-9 y=0\)
- D \(\frac{d^2 y}{d x^2}-y=0\)
Answer & Solution
Correct Answer
(B) \(\frac{d^2 y}{d x^2}+9 y=0\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & y=A \cos 3 x+B \sin 3 x \Rightarrow \frac{d y}{d x}=-3 A \sin 3 x+3 B \cos 3 x \\ & \frac{d^2 y}{d x^2}=-9 A \cos 3 x-9 B \sin 3 x=-9 y \\ & \Rightarrow \frac{d^2 y}{d x^2}+9 y=0 \text {. }\end{aligned}\)
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