AP EAMCET · Maths · Parabola
The co-ordinates of focus of the parabola \(5 x^2=-12 y\) are
- A \(\left(\frac{3}{5}, 0\right)\)
- B \(\left(\frac{-3}{5}, 0\right)\)
- C \(\left(0, \frac{3}{5}\right)\)
- D \(\left(0, \frac{-3}{5}\right)\)
Answer & Solution
Correct Answer
(D) \(\left(0, \frac{-3}{5}\right)\)
Step-by-step Solution
Detailed explanation
Given Parabola, \(\begin{aligned} 5 x^2 & =-12 y \quad \Rightarrow x^2=\frac{-12}{5} y \\ 4 a & =\frac{-12}{5} \Rightarrow a=\frac{-3}{5} \\ \text { Focus }=(0, a) & =\left(0, \frac{-3}{5}\right) \end{aligned}\) Hence, option (d) is correct.
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