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AP EAMCET · Maths · Area Under Curves

The area (in sq. units) of the region given by \(R=\left\{(x, y): \frac{y^2}{2} \leq x \leq y+4\right\}\) is

  1. A \(16\)
  2. B \(18\)
  3. C \(24\)
  4. D \(30\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(18\)

Step-by-step Solution

Detailed explanation

\(\frac{y^2}{2} = y+4 \Rightarrow y^2 - 2y - 8 = 0 \Rightarrow (y-4)(y+2) = 0 \Rightarrow y = -2, 4\) \(A = \int_{-2}^{4} \left( (y+4) - \frac{y^2}{2} \right) dy\) \(A = \left[ \frac{y^2}{2} + 4y - \frac{y^3}{6} \right]_{-2}^{4}\)…
From AP EAMCET
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