AP EAMCET · Maths · Probability
One ticket is selected at random from 50 tickets numbered \(00,01,02, \ldots \ldots 49\). The probability that sum of the digits is 10 , given that product of the digits is 9 , is
- A \(9 / 10\)
- B \(1 / 4\)
- C \(1 / 2\)
- D \(2 / 25\)
Answer & Solution
Correct Answer
(C) \(1 / 2\)
Step-by-step Solution
Detailed explanation
\(A=\) Sum of digits is 10 \(B=\) Product of digits is 9 \(A=\{19,28,37,46\}\) \(\Rightarrow n(A)=4\) \(n(B)=2\) \(n(S)=50\) \(B=\{19,33\}\) \(P(A)=\frac{4}{50}\) and \(P(B)=\frac{2}{50}\) \(P(A \cap B)=\frac{1}{50}\) Required probability,…
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