AP EAMCET · Maths · Circle
Number of circles intersecting \(x^2+y^2=4\), \(x^2+y^2-2 x-3=0\) and \(x^2+y^2-2 y-3=0\) orthogonally is
- A \(0\)
- B \(1\)
- C \(2\)
- D \(\infty\)
Answer & Solution
Correct Answer
(A) \(0\)
Step-by-step Solution
Detailed explanation
\(S_1 \equiv x^2+y^2=4\)...(i) \(S_2 \equiv x^2+y^2-2 x-3=0\)...(ii) \(S_3 \equiv x^2+y^2-2 y-3=0\)...(iii) Let \(S_4 \equiv x^2+y^2+2 g x+2 f y+c\) be the circle which is orthogonal with the circles \(S_1, S_2\) and \(S_3\). Condition of orthogonal,…
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