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AP EAMCET · Maths · Circle

Number of circles intersecting \(x^2+y^2=4\), \(x^2+y^2-2 x-3=0\) and \(x^2+y^2-2 y-3=0\) orthogonally is

  1. A \(0\)
  2. B \(1\)
  3. C \(2\)
  4. D \(\infty\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(0\)

Step-by-step Solution

Detailed explanation

\(S_1 \equiv x^2+y^2=4\)...(i) \(S_2 \equiv x^2+y^2-2 x-3=0\)...(ii) \(S_3 \equiv x^2+y^2-2 y-3=0\)...(iii) Let \(S_4 \equiv x^2+y^2+2 g x+2 f y+c\) be the circle which is orthogonal with the circles \(S_1, S_2\) and \(S_3\). Condition of orthogonal,…