AP EAMCET · Maths · Circle

Let \(S=0\) be the circle passing through the points \((2,0)\), \((1,-2),(-1,1)\). Then the point \((1,2)\)

A lies inside the circle \(\mathrm{S}=0\)
B lies outside the circle \(\mathrm{S}=0\)
C lies on the circle \(\mathrm{S}=0\)
D is the centre of the circle \(\mathrm{S}=0\)

Verified Solution

Answer & Solution

Correct Answer

(B) lies outside the circle \(\mathrm{S}=0\)

Step-by-step Solution

Detailed explanation

Let the equation of circle is as follows:- \[ (x-a)^2+(y-b)^2=r^2 \] Equation (i) is passing through the points \((2,0)\), \((1,-2) \&(-1,1)\). Then, we get \[ \begin{aligned} & (2-a)^2+(-b)^2=r^2 \\ & (1-a)^2+(-2-b)^2=r^2 \\ & (-1-a)^2+(1-b)^2=r^2 \end{aligned} \] Solving eqs.…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Explore more questions on app

From AP EAMCET

Explore more questions on app