AP EAMCET · Maths · Hyperbola
Let \(\mathrm{P}(\mathrm{h}, \mathrm{k})\) be the point of contact of the tangent to the hyperbola \(5 x^2-7 y^2-35=0\) which is parallel to the line \(\sqrt{2} x-y+\lambda=0\). If \(P\) lies in the third quadrant then \(3 h^2-2 k=\)
- A \(\frac{88}{9}\)
- B 36
- C 21
- D \(\frac{76}{3}\)
Answer & Solution
Correct Answer
(B) 36
Step-by-step Solution
Detailed explanation
The given eqn. of hyperbola is \(5 x^2-7 y^2-35=0\) ...(i) Differentiating (i), we get \(10 x-14 y \cdot y^{\prime}=0 \Rightarrow y^{\prime}=\frac{5 x}{7 y} \Rightarrow\left(y^{\prime}\right)_{(h, k)}=\frac{5 h}{7 k}\) \(\because\) Tangent line is parallel to…
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