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AP EAMCET · Maths · Properties of Triangles

Let a triangle ABC be inscribed in a circle of radius 2 units. If the 3 bisectors of the angles A, B and C are extended to cut the circle at A1, B1 and C1 respectively, then the value of AA1cosA2+BB1cosB2+CC1cosC2sinA+sinB+sinC2=

  1. A 4
  2. B 16
  3. C 25
  4. D 1
Verified Solution

Answer & Solution

Correct Answer

(B) 16

Step-by-step Solution

Detailed explanation

Consider the figure below. The triangle ABC is equilateral. Therefore, A=B=C=60°. Substitute the value in the given expression, AA1cosA2+BB1cosB2+CC1cosC2sinA+sinB+sinC2 =4cos60°2+4cos60°2+4cos60°2sin60°+sin60°+sin60°2 =4×3323322 =16
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