AP EAMCET · Maths · Matrices
Let \(A=\left[\begin{array}{ccc}1 & -1 & 2 \\ 0 & 3 & 4\end{array}\right], B=\left[\begin{array}{ccc}4 & 0 & -3 \\ -1 & -2 & -3\end{array}\right]\) and \(C=\left[\begin{array}{cccc}2 & -3 & 0 & 1 \\ 5 & -1 & -4 & 2 \\ -1 & 0 & 0 & 3\end{array}\right]\), what is \(A^T B\) ?
- A \(\left[\begin{array}{ccc}4 & 0 & -3 \\ -7 & -6 & -6 \\ 4 & -8 & -18\end{array}\right]\)
- B \(A^{\top} B\) is not defined
- C \(\left[\begin{array}{ccc}4 & -7 & 4 \\ 0 & -6 & -8 \\ -3 & 12 & 6\end{array}\right]\)
- D \(A^T B=0\)
Answer & Solution
Correct Answer
(A) \(\left[\begin{array}{ccc}4 & 0 & -3 \\ -7 & -6 & -6 \\ 4 & -8 & -18\end{array}\right]\)
Step-by-step Solution
Detailed explanation
\(A=\left[\begin{array}{ccc}1 & -1 & 2 \\ 0 & 3 & 4\end{array}\right], B=\left[\begin{array}{ccc}4 & 0 & -3 \\ -1 & -2 & -3\end{array}\right]\) and \(\quad C=\left[\begin{array}{cccc}2 & -3 & 0 & 1 \\ 5 & -1 & -4 & 2 \\ -1 & 0 & 0 & 3\end{array}\right]\) Now,…
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