AP EAMCET · Maths · Differentiation
If \(\mathrm{y}=\left(\log _{\mathrm{x}} \sin \mathrm{x}\right)^{\mathrm{x}}\), then \(\frac{\mathrm{dy}}{\mathrm{dx}}=\)
- A \(y\left[\frac{x \sin x}{\log \cos x}+\log (\log \sin x)+\frac{1}{\log x}-\log (\log x)\right]\)
- B \(y\left[\frac{x \cos x}{\log \sin x}-\log (\log \sin x)+\frac{1}{\log x}+\log (\log x)\right]\)
- C \(y\left[\frac{x \cot x}{\log \sin x}+\log (\log \sin x)-\frac{1}{\log x}-\log (\log x)\right]\)
- D \(y\left[\frac{x \cot x}{\log \sin x}-\log (\log \sin x)+\frac{1}{\log x}-\log x\right]\)
Answer & Solution
Correct Answer
(C) \(y\left[\frac{x \cot x}{\log \sin x}+\log (\log \sin x)-\frac{1}{\log x}-\log (\log x)\right]\)
Step-by-step Solution
Detailed explanation
Let \( y = \left(\log_x \sin x\right)^x \). Take natural logarithm on both sides: \( \log y = x \log \left(\log_x \sin x\right) \) Rewrite \(\log_x \sin x\) as \(\frac{\log \sin x}{\log x}\): \( \log y = x \log \left(\frac{\log \sin x}{\log x}\right) \) Differentiate both sides…
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