AP EAMCET · Maths · Straight Lines
If the straight line \(L \equiv 3 x+4 y-k=0\) cuts the line segment joining the points \(P(2,-1)\) and \(Q(1,1)\) in the ratio \(4: 1\), then the equation of the line parallel to the line \(y=x\) and concurrent with the lines \(P Q\) and \(L=0\) is
- A \(2 x-2 y+7=0\)
- B \(x-y+1=0\)
- C \(5 x-5 y-3=0\)
- D \(y=x+3\)
Answer & Solution
Correct Answer
(C) \(5 x-5 y-3=0\)
Step-by-step Solution
Detailed explanation
Point of intersection of given line \(L=0\) and line segment \(P Q\) is \[ R\left(\frac{(4 \times 1)+(1 \times 2)}{5}, \frac{(4 \times(1))+(1 \times(-1))}{5}\right)=R\left(\frac{6}{5}, \frac{3}{5}\right) \] Now, point \(R\) on the Line \(L=0\), So,…
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