AP EAMCET · Maths · Pair of Lines
If the combined equation of the lines joining the origin to the points of intersection of the curve \(x^2+y^2-2 x-4 y+2=0\) and the line \(x+y-2=0\) is \(\left(l_1 x+m_1 y\right)\) \(\left(l_2 \mathrm{x}+\mathrm{m}_2 \mathrm{y}\right)=0\), then \(l_1+l_2+\mathrm{m}_1+\mathrm{m}_2=\)
- A \(16\)
- B \(-6\)
- C \(-2\)
- D \(10\)
Answer & Solution
Correct Answer
(C) \(-2\)
Step-by-step Solution
Detailed explanation
\(x^2+y^2-2 x\left(\frac{x+y}{2}\right)-4 y\left(\frac{x+y}{2}\right)+2\left(\frac{x+y}{2}\right)^2=0\) \(x^2+y^2-(x^2+xy)-2y(x+y)+\frac{1}{2}(x^2+2xy+y^2)=0\) \(x^2+y^2-x^2-xy-2xy-2y^2+\frac{1}{2}x^2+xy+\frac{1}{2}y^2=0\) \(\frac{1}{2}x^2-2xy-\frac{1}{2}y^2=0\)…
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