AP EAMCET · Maths · Circle
If the circles \((x+a)^2+(y+b)^2=a^2\) and \((x+c)^2+(y+d)^2=d^2\) cut orthogonally, then \(b(b-2 d)=\)
- A \(c(c-2 a)\)
- B \(c(2 a-c)\)
- C \(d(2 c-a)\)
- D \(a(a-2 c)\)
Answer & Solution
Correct Answer
(B) \(c(2 a-c)\)
Step-by-step Solution
Detailed explanation
Given equation of circles are \(\begin{aligned} (x+a)^2+(y+b)^2 & =a^2 \\ \Rightarrow \quad x^2+y^2+2 a x+2 b y+b^2 & =0 \quad \ldots (i) \\ (x+c)^2+(y+d)^2 & =d^2 \\ \Rightarrow \quad x^2+y^2+2 c x+2 d y+c^2 & =0 \quad \ldots (ii) \end{aligned}\) From Eq. (i)…
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