AP EAMCET · Maths · Pair of Lines
If \(\theta\) is the angle between the lines \(x^2+2 h x y+b y^2=0\), then the angle between \(x^2+2 x y \sec \theta+y^2=0\) is
- A \(\theta\)
- B \(2 \theta\)
- C \(\frac{\theta}{2}\)
- D \(3 \theta\)
Answer & Solution
Correct Answer
(A) \(\theta\)
Step-by-step Solution
Detailed explanation
Given \(\theta\) is the angle between the lines \(x^2+2 h x y+b y^2=0\) To find Angle between \(x^2+2 x y \sec \theta+y^2=0\) Since, we know that angle between the line \(a x^2+2 h x y+b y^2=0\) is \(\tan \theta=\left|\frac{2 \sqrt{h^2-a b}}{a+b}\right|\) Here, \(\quad a=1\)…
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