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AP EAMCET · Maths · Quadratic Equation

If \(\alpha, \beta, \gamma\) are the roots of the equation \(x^3-12 x^2+k x-18=0\) and one of them is thrice the sum of the other two roots, then \(\alpha^2+\beta^2+\gamma^2-k=\)

  1. A \(115\)
  2. B \(41\)
  3. C \(56\)
  4. D \(57\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(57\)

Step-by-step Solution

Detailed explanation

\(\alpha+\beta+\gamma=12\) Given \(\alpha = 3(\beta+\gamma)\). So \(4(\beta+\gamma)=12 \implies \beta+\gamma=3 \implies \alpha=9\). Since \(\alpha=9\) is a root: \(9^3-12(9^2)+9k-18=0 \implies 729-972+9k-18=0 \implies 9k=261 \implies k=29\).…