ExamBro
ExamBro
AP EAMCET · Maths · Quadratic Equation

If \(\alpha, \beta\) and \(\gamma\) are the roots of the equation \(2 x^3+3 x^2-5 x-7=0\), then \(\frac{1}{\alpha^2}+\frac{1}{\beta^2}+\frac{1}{\gamma^2}=\)

  1. A \(-\frac{17}{49}\)
  2. B \(-\frac{23}{49}\)
  3. C \(\frac{55}{49}\)
  4. D \(\frac{67}{49}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{67}{49}\)

Step-by-step Solution

Detailed explanation

\(\alpha+\beta+\gamma = -\frac{3}{2}\) \(\alpha\beta+\beta\gamma+\gamma\alpha = -\frac{5}{2}\) \(\alpha\beta\gamma = \frac{7}{2}\) \(\frac{1}{\alpha^2}+\frac{1}{\beta^2}+\frac{1}{\gamma^2} = \frac{\beta^2\gamma^2+\alpha^2\gamma^2+\alpha^2\beta^2}{(\alpha\beta\gamma)^2}\)…