AP EAMCET · Maths · Quadratic Equation
If \(\alpha, \beta\) and \(\gamma\) are the roots of the equation \(2 x^3+3 x^2-5 x-7=0\), then \(\frac{1}{\alpha^2}+\frac{1}{\beta^2}+\frac{1}{\gamma^2}=\)
- A \(-\frac{17}{49}\)
- B \(-\frac{23}{49}\)
- C \(\frac{55}{49}\)
- D \(\frac{67}{49}\)
Answer & Solution
Correct Answer
(D) \(\frac{67}{49}\)
Step-by-step Solution
Detailed explanation
\(\alpha+\beta+\gamma = -\frac{3}{2}\) \(\alpha\beta+\beta\gamma+\gamma\alpha = -\frac{5}{2}\) \(\alpha\beta\gamma = \frac{7}{2}\) \(\frac{1}{\alpha^2}+\frac{1}{\beta^2}+\frac{1}{\gamma^2} = \frac{\beta^2\gamma^2+\alpha^2\gamma^2+\alpha^2\beta^2}{(\alpha\beta\gamma)^2}\)…
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