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AP EAMCET · Maths · Vector Algebra

If \(\mathbf{a}\) is collinear with \(\mathbf{b}=3 \hat{i}+6 \hat{j}+6 \hat{k}\) and \(\mathbf{a} \cdot \mathbf{b}=27\), then \(|\mathbf{a}|=\)

  1. A \(1\)
  2. B \(2\)
  3. C \(3\)
  4. D \(4\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(3\)

Step-by-step Solution

Detailed explanation

Let \(\mathbf{a}=x \hat{i}+y \hat{j}+z \hat{k}, \mathbf{b}=3 \hat{i}+6 \hat{j}+6 \hat{k}\) \(\mathbf{a} \cdot \mathbf{b}=27\) According to question, \(\mathbf{a}\) is a collinear with \(\mathbf{b}\), then \(\mathbf{a}=\lambda \mathbf{b}\) ...(i)…