AP EAMCET · Maths · Three Dimensional Geometry
If \(\vec{a}, \vec{b}, \vec{c}, \vec{d}\) are position vectors of 4 points such that \(2 \vec{a}+3 \vec{b}+5 \vec{c}-10 \vec{d}=\overrightarrow{0}\) then the ratio in which the line joining \(\vec{c}\) and \(\vec{d}\) divides the line segment joining \(\vec{a}\) and \(\vec{b}\) is
- A \(2: 3\)
- B \(-1: 2\)
- C \(2: 1\)
- D \(3: 2\)
Answer & Solution
Correct Answer
(D) \(3: 2\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & 2 \vec{a}+3 \vec{b}+5 \vec{c}-10 \vec{d}=\overrightarrow{0}, \Rightarrow 2 \vec{a}+3 \vec{b}=10 \vec{d}-5 \vec{c} \\ & \Rightarrow \frac{2 \vec{a}+3 \vec{b}}{5}=\frac{2 \vec{d}-\vec{c}}{1} \Rightarrow \frac{2 \vec{a}+3 \vec{b}}{3+2}=\frac{2…
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