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AP EAMCET · Maths · Trigonometric Ratios & Identities

If \(\cos A=\frac{7}{25}\) and \(\frac{3 \pi}{2} < A < 2 \pi\), then \(\cos \frac{A}{4}+\cos \frac{A}{2}-\cos 2 A=\)

  1. A \(\frac{1}{\sqrt{10}}+\frac{27}{625}\)
  2. B \(\frac{3}{\sqrt{10}}-\frac{27}{625}\)
  3. C \(\frac{3}{\sqrt{10}}+\frac{27}{625}\)
  4. D \(\frac{1}{\sqrt{10}}-\frac{27}{625}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{1}{\sqrt{10}}+\frac{27}{625}\)

Step-by-step Solution

Detailed explanation

Given, \(\quad \cos A=\frac{7}{25}\) and \(\frac{3 \pi}{2} < A < 2 \pi\) Then, \(\quad \cos 2 A=2\left(\frac{49}{625}\right)-1=\frac{98-625}{625}=-\frac{527}{625}\) \(\cos \frac{A}{2}=-\frac{4}{5}\) and \(\cos \frac{A}{4}=\frac{1}{\sqrt{10}}\) So,…