AP EAMCET · Maths · Determinants
If \(a \neq 1, b \neq-1, c \neq-1\) and the system of equations, \(x=a(y+z), y=b(z+x), z=c(x+y)\) has a non-trivial solution, then.
- A \(\frac{a}{a+1}+\frac{b}{b+1}+\frac{c}{c+1}=0\)
- B \(\frac{a}{a+1}+\frac{b}{b+1}+\frac{c}{c+1}=1\)
- C \(\frac{a b c}{(a+1)(b+1)(c+1)}=1\)
- D \(\frac{a+b+c}{(a+1)(b+1)(c+1)}=2\)
Answer & Solution
Correct Answer
(B) \(\frac{a}{a+1}+\frac{b}{b+1}+\frac{c}{c+1}=1\)
Step-by-step Solution
Detailed explanation
For system of homogeneous equation, if it has non-trivial solution, then \(\Delta=0\), so…
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