AP EAMCET · Maths · Straight Lines
If \(A(1,2,0), B(2,0,1), C(-3,0,2)\) are the vertices of \(\triangle A B C\), then the length of the internal bisector of \(\angle \mathrm{BAC}\) is
- A \(3 \sqrt{6}\)
- B \(\frac{2 \sqrt{14}}{3}\)
- C \(6 \sqrt{14}\)
- D \(\frac{2 \sqrt{6}}{3}\)
Answer & Solution
Correct Answer
(B) \(\frac{2 \sqrt{14}}{3}\)
Step-by-step Solution
Detailed explanation
Since, \(A B=\sqrt{6}, B C=\sqrt{26} \quad C A=\sqrt{24}\) \(\because A D\) is angle bisector \(\angle B A C\)…
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