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AP EAMCET · Maths · Complex Number

If \(1, \omega, \omega^2\) are the cube roots of unity, \(\mathrm{k}\) is positive integer and \(\left(1-\omega+\omega^2\right)^{3 \mathrm{k}}+\left(1-\omega^2+\omega\right)^{3 \mathrm{k}}=\left(1-\omega+\omega^2\right)^{3 \mathrm{k}+1}+\) \(\left(1+\omega-\omega^2\right)^{3 \mathrm{k}+1}\), then \(\mathrm{k}=\)

  1. A \(\mathrm{r}, \mathrm{r}, \in \mathbb{N}\)
  2. B \(2 r+1, r \in \mathbb{N}\)
  3. C \(4 r+1, r \in \mathbb{N}\)
  4. D \(3 r, r \in \mathbb{N}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\mathrm{r}, \mathrm{r}, \in \mathbb{N}\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & \text {}\left(1-\omega+\omega^2\right)^{3 k}+\left(1-\omega^2+\omega\right)^{3 k} \\ & =\left(1-\omega+\omega^2\right)^{3 k+1}+\left(1+\omega-\omega^2\right)^{3 k+1} \\ & \Rightarrow(-\omega-\omega)^{3 k}+\left(-\omega^2-\omega^2\right)^{3 k} \\ &…