AP EAMCET · Maths · Circle
Given, three collinear points \(A(3,1), B(7,-1)\) and \(C(5,0)\). The length of a tangent drawn from \(A\) to any circle that passes through \(B\) and \(C\) is ....... units.
- A \(2 \sqrt{10}\)
- B \(3 \sqrt{10}\)
- C \(\sqrt{10}\)
- D \(\sqrt{20}\)
Answer & Solution
Correct Answer
(C) \(\sqrt{10}\)
Step-by-step Solution
Detailed explanation
Since, we know that \(A C \cdot A B=A T^2\) ...(i) by using distance formula \(A C=\sqrt{(5-3)^2+(0-1)^2}\) \(=\sqrt{4+1}=\sqrt{5}\) \(\begin{aligned} A B & =\sqrt{(7-3)^2+(-1-1)^2} \\ & =\sqrt{16+4}=\sqrt{20}=2 \sqrt{5}\end{aligned}\)…
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