AP EAMCET · Maths · Probability
Four cards are drawn at random from a pack of playing cards. The probability of getting exactly two cards from the same suit and the remaining two cards from two different suits is
- A \(\frac{72 \times 169}{425 \times 49}\)
- B \(\frac{24 \times 169}{425 \times 49}\)
- C \(\frac{18 \times 169}{425 \times 49}\)
- D \(\frac{6 \times 169}{425 \times 49}\)
Answer & Solution
Correct Answer
(A) \(\frac{72 \times 169}{425 \times 49}\)
Step-by-step Solution
Detailed explanation
Four cards are drawn at random from pack of playing cards. Then, required probability…
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