AP EAMCET · Maths · Probability
For a binomial distribution with mean 6 and variance \(\mathrm{P}(\mathrm{X} \geq 2)=\)
- A \(\frac{19}{3^9}\)
- B \(1-\frac{2}{3^9}\)
- C \(1-\frac{19}{3^9}\)
- D \(\frac{2}{3^9}\)
Answer & Solution
Correct Answer
(C) \(1-\frac{19}{3^9}\)
Step-by-step Solution
Detailed explanation
Mean \(=6 \Rightarrow n p=6\) ...(i) Variance \(=2 \Rightarrow n p q=2\) ...(ii) Solving eqns. (i) and (ii) \(p=\frac{2}{3}, q=\frac{1}{3}\) and \(n=9\) Now, \(P(X \geq 2)=1-P(X < 2)\)…
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