AP EAMCET · Maths · Indefinite Integration
\(\begin{aligned} & \int \frac{x d x}{\sqrt[15]{\left(1+x^2\right)^{12}\left(2+x^2\right)^{18}}}=\alpha\left(\frac{1+x^2}{2+x^2}\right)^{1 / n}+C \Rightarrow \\ & \frac{n}{\alpha}=\end{aligned}\)
- A \(6\)
- B \(4\)
- C \(2\)
- D \(8\)
Answer & Solution
Correct Answer
(C) \(2\)
Step-by-step Solution
Detailed explanation
\begin{aligned} I & =\int \frac{x d x}{\sqrt[15]{\left(1+x^2\right)^{12}\left(2+x^2\right)^{18}}} \\ & =\int \frac{x d x}{\left(1+x^2\right)^{12 / 15}\left(2+x^2\right)^{18 / 15}} \\ & =\int \frac{x d x}{\left(1+x^2\right)^{4 / 5}\left(2+x^2\right)^{6 / 5}} \\ & =\int \frac{x d…
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