AP EAMCET · Maths · Application of Derivatives
A particle is moving along a line according to the law \(S=t^3-3 t^2+4 t-2\) where \(\mathrm{S}\) is measured in metres and \(t\) is measured in seconds. Then the velocity (in \(\mathrm{mt} / \mathrm{sec}\) ) of the particle when its acceleration is zero is
- A \(2\)
- B \(\frac{1}{4}\)
- C \(\frac{17}{4}\)
- D \(1\)
Answer & Solution
Correct Answer
(D) \(1\)
Step-by-step Solution
Detailed explanation
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