AP EAMCET · Maths · Vector Algebra
\(\mathbf{a}, \mathbf{b}, \mathbf{c}\) are three vectors such that \(|\mathbf{a}|=3\), \(|\mathbf{b}|=5,|\mathbf{c}|=7\). If \(\mathbf{a}, \mathbf{b}, \mathbf{c}\) are perpendicular to the vectors \(\mathbf{b}+\mathbf{c}, \mathbf{c}+\mathbf{a}, \mathbf{a}+\mathbf{b}\) respectively, then \(\sqrt{(\mathbf{a}+\mathbf{b}+\mathbf{c})^2-2}=\)
- A 15
- B 9
- C 22
- D 25
Answer & Solution
Correct Answer
(B) 9
Step-by-step Solution
Detailed explanation
We have, \[ |\mathbf{a}|=3,|\mathbf{b}|=5,|\mathbf{c}|=7 \] \(\mathbf{a}\) is perpendicular to \((\mathbf{b}+\mathbf{c})\) and \(\mathbf{b}\) is perpendicular to \(\mathbf{c}+\mathbf{a}\) So, \(\mathbf{b} \cdot(\mathbf{c}+\mathbf{a})=0\) and \(\mathbf{c}\) is perpendicular to…
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