AP EAMCET · Maths · Trigonometric Ratios & Identities
\(a, b, c\) are the sides of a scalene triangle \(A B C\). If angles \(\alpha, \beta, \gamma\) lie between 0 and \(\pi\) such that \(\cos \alpha=\frac{a}{b+c}, \cos \beta=\frac{b}{c+a}\) and \(\cos \gamma=\frac{c}{a+b}\), then \(\tan ^2 \frac{\alpha}{2}+\tan ^2 \frac{\beta}{2}+\tan ^2 \frac{\gamma}{2}=\)
- A \(\frac{1}{3}\)
- B 2
- C 1
- D \(\frac{3}{2}\)
Answer & Solution
Correct Answer
(C) 1
Step-by-step Solution
Detailed explanation
It is given \(\cos \alpha=\frac{a}{b+c}\) \(\Rightarrow \quad \frac{1-\tan ^2 \frac{\alpha}{2}}{1+\tan ^2 \frac{\alpha}{2}}=\frac{a}{b+c}\) On applying componendo and dividendo law, we get \(\frac{2 \tan ^2 \alpha / 2}{2}=\frac{b+c-a}{b+c+a}\)…
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