AP EAMCET · Maths · Probability
\(A\) and \(B\) each select one number at random from the distinct numbers \(1,2,3, \ldots, n\) and the probability that the number selected by \(A\) is less than the number selected by \(B\) is \(\frac{1009}{2019}\). Now, the probability that the number selected by \(B\) is the number immediately next to the number selected by \(A\) is
- A \(\frac{2018}{2019}\)
- B \(\frac{2018}{(2019)^2}\)
- C \(\frac{2000}{(2019)}\)
- D \(\frac{2000}{(2019)^2}\)
Answer & Solution
Correct Answer
(B) \(\frac{2018}{(2019)^2}\)
Step-by-step Solution
Detailed explanation
It is given that, \(A\) and \(B\) each select one number at random from the distinct numbers 1,2 , \(3, \ldots, n\), then the probability that the number selected by \(A\) is less than the number selected by \(B\) is…
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