AP EAMCET · Maths · Parabola
\(A(-2,9)\) and \(B(1,6)\) are two points on the curve \(y=x^2+5\). The coordinates of the point \(\mathrm{C}\) on the curve such that the tangent drawn at \(\mathrm{A}\) is parallel to the chord \(\mathrm{BC}\), is
- A \((-5,30)\)
- B \((0,5)\)
- C \((-9,86)\)
- D \((6,41)\)
Answer & Solution
Correct Answer
(A) \((-5,30)\)
Step-by-step Solution
Detailed explanation
\[ \begin{aligned} & \text {} \because y=x^2+5 \\ & \Rightarrow y^{\prime}=2 x \end{aligned} \] Equation of tangent line at point \(A(-2,9)\) : \[ \begin{aligned} & (y-9)=(2 x-2)(x+2) \\ & \Rightarrow y-9=-4 x-8 \Rightarrow y=-4 x+1 \end{aligned} \] let coordinate of…
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