AP EAMCET · Chemistry · Carboxylic Acid Derivatives
Wurtz reaction of bromoethane gives \(n\)-butane. Sodium salt of \(X\) on heating with sodalime also results in \(n\)-butane. Compound \(X\) is
- A \(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{COOH}\)
- B \(\mathrm{CH}_3\left(\mathrm{CH}_2\right)_3 \mathrm{COOH}\)
- C \(\mathrm{CH}_3\left(\mathrm{CH}_2\right)_4 \mathrm{COOH}\)
- D \(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{COOH}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{CH}_3\left(\mathrm{CH}_2\right)_3 \mathrm{COOH}\)
Step-by-step Solution
Detailed explanation
In Wurtz reaction, two molecules of bromoethane react with 2 molecules of sodium to form \(n\)-butane.…
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