AP EAMCET · Chemistry · Chemical Bonding and Molecular Structure
What is the hybridisation of \(\mathrm{Be}\) in \(\mathrm{BeF}_2\) molecule?
- A \(d s p^2\)
- B \(s p^2 d\)
- C \(\mathrm{sp}\)
- D \(s p^3\)
Answer & Solution
Correct Answer
(C) \(\mathrm{sp}\)
Step-by-step Solution
Detailed explanation
Hybridisation state of \(\mathrm{Be}\) in \(\mathrm{BeF}_2\) is \(s p\). \(\begin{aligned} & \mathrm{F}-\mathrm{Be}-\mathrm{F} \\ & \mathrm{H}=\frac{1}{2}(V+M-C+A) \\ &=\frac{1}{2}(2+2-0+0)=2(s p) \end{aligned}\) where, \(V=\) number of valence electrons of \(\mathrm{Be}=2\)…
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