AP EAMCET · Chemistry · Structure of Atom
The ratio of ground state energy of \(\mathrm{Li}^{2+}, \mathrm{He}^{+}, \mathrm{H}\) is
- A \(3: 2: 1\)
- B \(1: 2: 3\)
- C \(9: 4: 1\)
- D \(1: 4: 9\)
Answer & Solution
Correct Answer
(C) \(9: 4: 1\)
Step-by-step Solution
Detailed explanation
Ground state energy of hydrogen like atom is \(E=-13.6 \times \frac{Z^2}{n^2}\) All are in ground state i.e \(\mathrm{n}=1\) \(\therefore E \propto Z^2\) \(\therefore \quad\) The ratio of ground state energy of…
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